/* * Copyright (c) 2017 Thomas Pornin * * Permission is hereby granted, free of charge, to any person obtaining * a copy of this software and associated documentation files (the * "Software"), to deal in the Software without restriction, including * without limitation the rights to use, copy, modify, merge, publish, * distribute, sublicense, and/or sell copies of the Software, and to * permit persons to whom the Software is furnished to do so, subject to * the following conditions: * * The above copyright notice and this permission notice shall be * included in all copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, * EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF * MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND * NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS * BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN * ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN * CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE * SOFTWARE. */ #include "inner.h" /* * Constant-time division. The divisor must not be larger than 16 bits, * and the quotient must fit on 17 bits. */ static uint32_t divrem16(uint32_t x, uint32_t d, uint32_t *r) { int i; uint32_t q; q = 0; d <<= 16; for (i = 16; i >= 0; i --) { uint32_t ctl; ctl = LE(d, x); q |= ctl << i; x -= (-ctl) & d; d >>= 1; } if (r != NULL) { *r = x; } return q; } /* see inner.h */ void br_i15_muladd_small(uint16_t *x, uint16_t z, const uint16_t *m) { /* * Constant-time: we accept to leak the exact bit length of the * modulus m. */ unsigned m_bitlen, mblr; size_t u, mlen; uint32_t hi, a0, a, b, q; uint32_t cc, tb, over, under; /* * Simple case: the modulus fits on one word. */ m_bitlen = m[0]; if (m_bitlen == 0) { return; } if (m_bitlen <= 15) { uint32_t rem; divrem16(((uint32_t)x[1] << 15) | z, m[1], &rem); x[1] = rem; return; } mlen = (m_bitlen + 15) >> 4; mblr = m_bitlen & 15; /* * Principle: we estimate the quotient (x*2^15+z)/m by * doing a 30/15 division with the high words. * * Let: * w = 2^15 * a = (w*a0 + a1) * w^N + a2 * b = b0 * w^N + b2 * such that: * 0 <= a0 < w * 0 <= a1 < w * 0 <= a2 < w^N * w/2 <= b0 < w * 0 <= b2 < w^N * a < w*b * I.e. the two top words of a are a0:a1, the top word of b is * b0, we ensured that b0 is "full" (high bit set), and a is * such that the quotient q = a/b fits on one word (0 <= q < w). * * If a = b*q + r (with 0 <= r < q), then we can estimate q by * using a division on the top words: * a0*w + a1 = b0*u + v (with 0 <= v < b0) * Then the following holds: * 0 <= u <= w * u-2 <= q <= u */ hi = x[mlen]; if (mblr == 0) { a0 = x[mlen]; memmove(x + 2, x + 1, (mlen - 1) * sizeof *x); x[1] = z; a = (a0 << 15) + x[mlen]; b = m[mlen]; } else { a0 = (x[mlen] << (15 - mblr)) | (x[mlen - 1] >> mblr); memmove(x + 2, x + 1, (mlen - 1) * sizeof *x); x[1] = z; a = (a0 << 15) | (((x[mlen] << (15 - mblr)) | (x[mlen - 1] >> mblr)) & 0x7FFF); b = (m[mlen] << (15 - mblr)) | (m[mlen - 1] >> mblr); } q = divrem16(a, b, NULL); /* * We computed an estimate for q, but the real one may be q, * q-1 or q-2; moreover, the division may have returned a value * 8000 or even 8001 if the two high words were identical, and * we want to avoid values beyond 7FFF. We thus adjust q so * that the "true" multiplier will be q+1, q or q-1, and q is * in the 0000..7FFF range. */ q = MUX(EQ(b, a0), 0x7FFF, q - 1 + ((q - 1) >> 31)); /* * We subtract q*m from x (x has an extra high word of value 'hi'). * Since q may be off by 1 (in either direction), we may have to * add or subtract m afterwards. * * The 'tb' flag will be true (1) at the end of the loop if the * result is greater than or equal to the modulus (not counting * 'hi' or the carry). */ cc = 0; tb = 1; for (u = 1; u <= mlen; u ++) { uint32_t mw, zl, xw, nxw; mw = m[u]; zl = MUL15(mw, q) + cc; cc = zl >> 15; zl &= 0x7FFF; xw = x[u]; nxw = xw - zl; cc += nxw >> 31; nxw &= 0x7FFF; x[u] = nxw; tb = MUX(EQ(nxw, mw), tb, GT(nxw, mw)); } /* * If we underestimated q, then either cc < hi (one extra bit * beyond the top array word), or cc == hi and tb is true (no * extra bit, but the result is not lower than the modulus). * * If we overestimated q, then cc > hi. */ over = GT(cc, hi); under = ~over & (tb | LT(cc, hi)); br_i15_add(x, m, over); br_i15_sub(x, m, under); }