2 Test that lldb persistent types works correctly.
5 from __future__ import print_function
11 from lldbsuite.test.lldbtest import *
13 class PersistenttypesTestCase(TestBase):
15 mydir = TestBase.compute_mydir(__file__)
17 @expectedFailureWindows("llvm.org/pr21765")
18 def test_persistent_types(self):
19 """Test that lldb persistent types works correctly."""
22 self.runCmd("file a.out", CURRENT_EXECUTABLE_SET)
24 self.runCmd("breakpoint set --name main")
26 self.runCmd("run", RUN_SUCCEEDED)
28 self.runCmd("expression struct $foo { int a; int b; };")
30 self.expect("expression struct $foo $my_foo; $my_foo.a = 2; $my_foo.b = 3;",
31 startstr = "(int) $0 = 3")
33 self.expect("expression $my_foo",
34 substrs = ['a = 2', 'b = 3'])
36 self.runCmd("expression typedef int $bar")
38 self.expect("expression $bar i = 5; i",
39 startstr = "($bar) $1 = 5")
41 self.runCmd("expression struct $foobar { char a; char b; char c; char d; };")
44 self.expect("memory read foo -t $foobar",
45 substrs = ['($foobar) 0x', ' = ', "a = 'H'","b = 'e'","c = 'l'","d = 'l'"]) # persistent types are OK to use for memory read
47 self.expect("memory read foo -t foobar",
48 substrs = ['($foobar) 0x', ' = ', "a = 'H'","b = 'e'","c = 'l'","d = 'l'"],matching=False,error=True) # the type name is $foobar, make sure we settle for nothing less
50 self.expect("expression struct { int a; int b; } x = { 2, 3 }; x",
51 substrs = ['a = 2', 'b = 3'])
53 self.expect("expression struct { int x; int y; int z; } object; object.y = 1; object.z = 3; object.x = 2; object",
54 substrs = ['x = 2', 'y = 1', 'z = 3'])
56 self.expect("expression struct A { int x; int y; }; struct { struct A a; int z; } object; object.a.y = 1; object.z = 3; object.a.x = 2; object",
57 substrs = ['x = 2', 'y = 1', 'z = 3'])